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I wish to get the file extension of an image I am uploading, but I just get an array back. 我希望获得我上传的图像的文件扩展名，但我只是得到了一个数组。

$userfile_name = $_FILES['image']['name'];$userfile_extn = explode(".", strtolower($_FILES['image']['name']));

Is there a way to just get the extension itself? 有没有办法让扩展本身？

#1楼

参考：

#2楼

怎么样

$ext = array_pop($userfile_extn);

#3楼

No need to use string functions. 无需使用字符串函数。 You can use something that's actually designed for what you want: : 你可以使用实际设计的东西： ：

$path = $_FILES['image']['name'];$ext = pathinfo($path, PATHINFO_EXTENSION);

#4楼

A better method is using strrpos + substr (faster than explode for that) : 一个更好的方法是使用strrpos + substr（比爆炸更快）：

$userfile_name = $_FILES['image']['name'];$userfile_extn = substr($userfile_name, strrpos($userfile_name, '.')+1);

But, to check the type of a file, using mime_content_type is a better way : 但是，要检查文件的类型，使用mime_content_type是一种更好的方法： ：//www.php.net/manual/en/function.mime-content-type.php

#5楼

You could try with this for mime type 您可以尝试使用此类型的mime

$image = getimagesize($_FILES['image']['tmp_name']);

$image['mime'] will return the mime type. $image['mime']将返回mime类型。

This function doesn't require GD library. 此功能不需要GD库。 You can find the documentation . 你可以在找到文档。

This returns the mime type of the image. 这将返回图像的mime类型。

Some people use the $_FILES["file"]["type"] but it's not reliable as been given by the browser and not by PHP. 有些人使用$_FILES["file"]["type"]但它不像浏览器而不是PHP那样可靠。

You can use pathinfo() as ThiefMaster suggested to retrieve the image extension. 您可以使用pathinfo()作为ThiefMaster建议检索图像扩展名。

First make sure that the image is being uploaded successfully while in development before performing any operations with the image. 首先确保在开发过程中成功上载图像，然后再对图像执行任何操作。

#6楼

This will work as well: 这也可以：

$array = explode('.', $_FILES['image']['name']);$extension = end($array);

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